8a^2-0.5=0

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Solution for 8a^2-0.5=0 equation: 



8a^2-0.5=0

a = 8; b = 0; c = -0.5;
Δ = b2-4ac
Δ = 02-4·8·(-0.5)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$


$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4}{2*8}=\frac{-4}{16}
=-1/4
$


$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4}{2*8}=\frac{4}{16}
=1/4
$

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